Thread:JaimeMA/@comment-30117738-20170421163624/@comment-30117738-20170421215825

Strategy:  I keep all my rooms in text mode to trigger anomalies which then give me extra candles. I play about 1 1/2 hours a day, sometimes only in 1/2 hour chunks. In that time I can usually generate at least 100 items, sometimes more. If I have the energy, I may use a dinner to get more energy, thus being able to get the desired 200 items.

When you use the Amulet of rarities it reduces the number of special items needed for the room. For example, in high explorer level you need 25 items to play. When you use the Amulet (sorry i called it a talisman above) of rarities, ite reduces the number needed for each search to 20 since it reduces the required item by 20% for 24 hours. This is the best amulet to have when there is an event on!

Being at the 15% level in the room means I have searched it 15 times because that level requires 100 searches to go to academician level. So have to search 85 more times. 85 times 20 per serch means I will need 1700 total items. In the past I have used the amulet starting at noon one day so I can play two days - the afternoon of one and the morning of the other before the 24 time period runs out. And  I would do that when I had about 400 earned items. But that is a waste of the amulet,  So now I seach all the other rooms to get all the apecial items I will need to finish the room with only one amulet of rareties needed. If I also engage the Valentine Amulet, it reduces the energy requirement by 10% meaning that I will only have to use 27 energy points to search the room. 85 searches needed times 27 energy cost means that I will need 2295 in energy to finish off. Right now my total energy cap is at 2955 so I can get the avatar when my energy level is full. I only use the amulet when I am in the pro and high explorer levels.

I'm sure there is a general strategy guide somewhere but I learned by adding a bit of information at a time because the game is quite complex.

Ask if you have more questions. Happy to answer.